2)3x/(3x+3)=(5x+3)/(3x+3),
(2x+3)/(3x+3)=0,∴x=-3/2,代入分母≠0
3）2（x+1）/(x^2-1)=4/(x^2-1)
(2x-2)/(x^2-1)=0,∴x=1,代入分母=0，无解
4）[5x-5-(x+1)]/[x(x+1)(x-1)]
=(4x-6)/[x(x+1)(x-1)]
=0
∴x=3/2代入分母≠0
(2x+3)/(3x+3)=0,∴x=-3/2,代入分母≠0
3）2（x+1）/(x^2-1)=4/(x^2-1)
(2x-2)/(x^2-1)=0,∴x=1,代入分母=0，无解
4）[5x-5-(x+1)]/[x(x+1)(x-1)]
=(4x-6)/[x(x+1)(x-1)]
=0
∴x=3/2代入分母≠0
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第1个回答 2011-03-06
先去分母
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