请各位大师指点迷津！！寡人有奖励！两道数学题！

Question

1.24^2b^3c(x+y-z)-18a^3bc^2(z-y-x)-36abc(x-z+y)

2.24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xyz^3(z-x-y)

Answer 1

是分解因式吧：
1.24a^2b^3c(x+y-z)-18a^3bc^2(z-y-x)-36abc(x-z+y)
=24a^2b^3c(x+y-z)+18a^3bc^2(x+y-z)-36abc(x+y-z)
=(x+y-z)(24a^2b^3c+18a^3bc^2-36abc)
=(x+y-z)*6abc(4ab^2+3a^2c-6)
=6abc(x+y-z)(4ab^2+3a^2c-6)

2.24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xyz^3(z-x-y)
=24xy^2z^2(x+y-z)+32xyz(x+y-z)^2-8xyz^3(x+y-z)
=(x+y-z)(24xy^2z^2+32xyz-8xyz^3)
=(x+y-z)*8xyz(3yz+4-z^2)
=8xyz(x+y-z)(3yz+4-z^2)