android怎么在服务器和客户端之间传输图片？

Question

这是我的服务端的代码：
String imagePath="/home/shenlei/tupian/jiaofu.jpg";
File file =new File(imagePath);
FileInputStream inputstream = new FileInputStream(file);
OutputStream out = resp.getOutputStream();
//拷贝输出
byte[] buf = new byte[1024];
int count = 0;
while ((count =inputstream.read(buf)) >= 0) {
out.write(buf, 0, count);
}
inputstream.close();
out.close();

}
这是客户端的接受的代码：
// 取得图片字节流
HttpEntity httpEntity = response.getEntity();
InputStream is = httpEntity.getContent();
bitmap = BitmapFactory.decodeStream(is);
is.close();
但是获取的图像没有现实出来：
ImageView image = (ImageView) findViewById(R.id.detail_img);
image.setImageBitmap(HttpUtil.bitmap);

这是log
07-28 12:52:13.861: D/libc(25884): [NET] getaddrinfo+,hn 13(0x3139322e313638),sn(),family 0,flags 4
07-28 12:52:13.861: D/libc(25884): [NET] getaddrinfo-, SUCCESS
07-28 12:52:13.861: D/libc(25884): [NET] getaddrinfo+,hn 13(0x3139322e313638),sn(),family 0,flags 4
07-28 12:52:13.861: D/libc(25884): [NET] getaddrinfo-, SUCCESS
07-28 12:52:13.861: D/libc(25884): [NET] getaddrinfo+,hn 13(0x3139322e313638),sn(),family 0,flags 4
07-28 12:52:13.861: D/libc(25884): [NET] getaddrinfo-, SUCCESS
07-28 12:52:13.871: I/global(25884): call createSocket() return a new socket.
07-28 12:52:13.871: D/libc(25884): [NET] getaddrinfo+,hn 13(0x3139322e313638),sn(),family 0,flags 4
07-28 12:52:13.871: D/libc(25884): [NET] getaddrinfo-, SUCCESS

Answer 1

android客户端和java服务端之间可以用socket来传输图片。
服务器端代码：
import java.io.DataInputStream;
import java.io.DataOutputStream;
import java.io.FileInputStream;
import java.io.IOException;
import java.net.InetSocketAddress;
import java.net.ServerSocket;
import java.net.Socket;

public class Server02 {
public static void main(String[] args) {
try {
ServerSocket server = new ServerSocket(40000);
Socket socket = server.accept();
DataInputStream dos = new DataInputStream(socket.getInputStream());
int len = dos.available();
System.out.println("len = "+len);
byte[] data = new byte[len];
dos.read(data);

System.out.println("data = "+data);
dos.close();
socket.close();
server.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
客户端代码：
[java] view plaincopy
imageView02 = (ImageView)findViewById(R.id.image02);
button02 = (Button)findViewById(R.id.Button02);
button02.setOnClickListener(new OnClickListener(){
public void onClick(View arg0) {
Socket socket;
try {
socket = new Socket("192.168.1.203",40000);
DataOutputStream out = new DataOutputStream(socket.getOutputStream());

Bitmap bitmap = BitmapFactory.decodeResource(getResources(), R.drawable.qt);
imageView02.setImageBitmap(bitmap);
ByteArrayOutputStream baos = new ByteArrayOutputStream();
//读取图片到ByteArrayOutputStream
bitmap.compress(Bitmap.CompressFormat.PNG, 100, baos);
byte[] bytes = baos.toByteArray();
out.write(bytes);

System.out.println("bytes--->"+bytes);
out.close();
socket.close();
} catch (UnknownHostException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
});

}

Answer 2

服务端只要提供给客户端 图片下载的请求地址就行了，

你把图片都放在一个服务器某目录下，做一个请求的URl

Answer 3

本地获取服务端的话，是服务端返回一个url，然后本地加载网络图片bitmap流，然后加载到imageview里，服务端的话，就是本地图片上传了

Answer 4

上传与下载

Answer 5

具体什么问题。