1/2x+1/x(x-2)+1/(x-2)(x-4)+1/(x+4)(x+6)=2解方程，急急急

Answer 1

x-1/x+1 + x-4/x+4 =x-2/x+2 + x-3/x+3
1-2/(x+1)+1-8/(x+4)=1-4/(x+2)+1-6/(x-3)
1/(x+1)+4/(x+4)=2/(x+2)+3/(x+3)
4/(x+4)-3/(x+3)=2/(x+2)-1/(x+1)
x/(x+4)(x+3)=x/(x+1)(x+2)
x[(x^2+7x+12)-(x^2+3x+2)]=0
x(4x+10)=0
x=0或x=-5/2
经检验，符合
即得原方程的解为x=0或-5/2