我们老师的结果是-19/4 而且我们都没意见但还是看不懂
追答就你写的这题而言,是-29/4
你实在不信的话,再去问问老师,让他重新解一下,看是多少
3\/4[4\/3(1\/2x-1\/4)-8]-3\/2x=1 解方程X 结果不等于-29\/4
共两个答案:(29加减根号下889)\/4
3\/4[4\/3(1\/2x-1\/4)-8]=3\/2x-7 解方程,要过程
图
解方程(3\/4)(4\/3)(1\/2x-1\/4)-8]=(3\/2)x时李明同学认为按照解一元一次...
(3\/4)×(4\/3)(1\/2x-1\/4)-(3\/4)×8=(3\/2)x (1\/2x-1\/4)-6=(3\/2)x 1\/2x-1\/4-6=(3\/2)x 移项 (3\/2)x-(1\/2)x=-6-1\/4 (3\/2-1\/2)x=-(6+1\/4)x=-6又1\/4
3\/4{4\/3(1\/2X-1\/4)-8}=3\/2x+1(用两种方法解答) 步骤
-X=29\/4 X=-29\/4 4\/3[1\/2X-1\/4]-8=[3\/2X+1]*4\/3 2\/3X-1\/3-8=2X+4\/3 2\/3X-2X=4\/3+1\/3+8 -4\/3X=29\/3 X=-29\/4
3\/4【4\/3(1\/2x-1\/4)-8】=3\/2x 用简便方法解
3\/4[4\/3(1\/2x-1\/4)-8]=3\/2x 3\/4×4\/3(1\/2x-1\/4)-8×3\/4=3\/2x 1\/2x-1\/4-6=3\/2x 3\/2x-1\/2x=25\/4 1\/x=25\/4 x=4\/25
3\/4【4\/3(1\/2x-1)-8】=3\/2x-1 过程
同学 题目应该是 3\/4{4\/3(1\/2X-1\/4)-8}=3\/2x+1 (1\/2X-1\/4)-8*3\/4=3\/2X+1 1\/2X-3\/2X=1+6+1\/4 -X=29\/4 X=-29\/4 4\/3[1\/2X-1\/4]-8=[3\/2X+1]*4\/3 2\/3X-1\/3-8=2X+4\/3 2\/3X-2X=4\/3+1\/3+8 -4\/3X=29\/3 X=-29\/4 ...
3\/4括号4\/3括号,1\/2X,减去,1\/4括号,减八反括号等于3\/2x十1怎么得出来...
3\/4×[4\/3×(x\/2-1\/4)-8]=3x\/2+1 解:3\/4×[2x\/3-1\/3-8]=3x\/2+1 3\/4×[2x\/3-25\/3]=3x\/2+1 x\/2-25\/4=3x\/2+1 3x\/2-x\/2=-25\/4-1 x=-29\/4。解题不等于6。
3\/4[4\/3(1\/2x-1\/4)-8]=3\/2x 求x的值
原式=3\/4[2\/3x-1\/3-8]=3\/2x 1\/2x-1\/4-6=3\/2x 1\/2x-3\/2x=-5\/4 -1x=-5\/4 x=5\/4 我不知道我写的对不对,要是写错了,请你原谅。
3\/4{4\/3[1\/2(x-1\/4)]-8}=3\/2x
解:3\/4{4\/3[1\/2(x-1\/4)]-8}=3\/2x [1\/2(x-1\/4)]-6=3\/2x (x-1\/4)-12=3x -12-1\/4=3x-x 2x=-49\/4 x=-49\/8
3\/4[4\/3(1\/2x-1\/4)-8]=3\/2x-5\/4
3\/4[4\/3(1\/2x-1\/4)-8]=3\/2x-5\/4 (1\/2x-1\/4)-6=3\/2x-5\/4 1\/2x-1\/4-6=3\/2x-5\/4 3\/2x-1\/2x=5\/4-1\/4-6 x=-5