C语言中1+2+3+4+....100+99+98+97+....1怎么计算

Answer 1

# include<stdio.h>
void main()
{
int i,n,s;
for(i=1;i<100;i++)
{
n=i+i;
s+=n;
}
s+=100;
printf("%d\n",s);
}

Answer 2

#include<iostream>

using namespace std;

int main()
{
int i;
int sum = 0;
int num;
for ( i = 1; i <= 199; i++ )
{
num = i <= 100 ? i : (200-i);
sum += num;
}
cout << sum << endl;
system("pause");
return 0;
}

Answer 3

i=N，when i<101,i++
else i--
具体自己再想想吧。好久不用了

Answer 4

#include<stdio.h>
void main()
{
int i,s=0;
for(i=1;i<=100;i++)
s=s+i;

printf("1加到100=%d",s);
getch();
}